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Old 05-01-06, 22:08   #1
galmati

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Default puterea la x ohmi???

As vrea sa ma lamureasca cineva cu sta treaba cu puterile care se dau pentru un anumit amplificator.
De exemplu un amplificator monobloc care are 300w@4ohm si 600w@2ohm daca este legat la un dif de 2x4ohm ce putere va avea?
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Old 05-01-06, 22:18   #2
pesteimputit

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600w la 2 ohmi
un dif de 2*4 ohmi se poate lega fie in 8 fie in 2 ohmi
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Old 05-01-06, 22:18   #3
viperu

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daca legi cele doua bobine de 4ohm in paralel o sa ai o impedanta de 2ohm iar daca le legi in serie atunci vei avea o impedanta de 8ohm.

deci 600w daca legi bobinele in paralel si mai putin de 300w daca legi bobinele in serie.
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Old 05-01-06, 22:49   #4
galmati

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Mersi.Acum am inteles si imi dau seama ce logic era.
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Old 17-01-06, 08:56   #5
catharsis3k

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Si nu uita ca este de dorit sa ramai mereu la o impedanta cat mai mare. In marea majoritate a timpurilor si mai ales la amplificatoarele mai slabe, cu cat urca putere si scade impedanta cu atat ai mai multe distorsiuni.

din acest motiv eu prefer sa-mi tin amplificatorul in 2x300W @ 4ohms decat in 2X600W @ 2ohms.
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